Add a new input in a row using jquery

You can add a new input field in a row using jQuery by appending a new HTML element to the row. Here is an example:

// assume you have a table with a class of "myTable" and a row with a class of "myRow"
$('.myRow').append('<input type="text" name="newInput" />');

This will add a new input field with the name "newInput" to the end of each row with the class "myRow".

If you want to add the input field to a specific row, you can use the find method to select the row and then append the input field:

$('#myTable tr:eq(1)').find('.myRow').append('<input type="text" name="newInput" />');

This will add the input field to the second row of the table.

You can also use the after method to add the input field after a specific element in the row:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').after('<input type="text" name="newInput" />');

This will add the input field after the second column of the second row.

You can also use a template engine like Handlebars or Mustache to generate the input field and append it to the row.

You can also use the clone method to clone an existing input field and append it to the row:

$('#myTable tr:eq(1)').find('.myRow').find('input').clone().appendTo('.myRow');

This will clone the first input field in the row and append it to the end of the row.

You can also use the tmpl method to generate a new input field and append it to the row:

var tmpl = '<input type="text" name="newInput" />';
$('#myTable tr:eq(1)').find('.myRow').append(tmpl);

This will generate a new input field with the name "newInput" and append it to the end of the row.

You can also use the append method with a function to generate the input field and append it to the row:

$('#myTable tr:eq(1)').find('.myRow').append(function() {
  return '<input type="text" name="newInput" />';
});

This will generate a new input field with the name "newInput" and append it to the end of the row.

You can also use the after method with a function to generate the input field and append it to the row:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').after(function() {
  return '<input type="text" name="newInput" />';
});

This will generate a new input field with the name "newInput" and append it to the end of the second column of the second row.

You can also use the insertAfter method to insert the input field after a specific element in the row:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').insertAfter('<input type="text" name="newInput" />');

This will insert the input field after the second column of the second row.

You can also use the insertBefore method to insert the input field before a specific element in the row:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').insertBefore('<input type="text" name="newInput" />');

This will insert the input field before the second column of the second row.

You can also use the replaceAll method to replace a specific element in the row with the input field:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').replaceAll('<input type="text" name="newInput" />');

This will replace the second column of the second row with the input field.

You can also use the replaceWith method to replace a specific element in the row with the input field:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').replaceWith('<input type="text" name="newInput" />');

This will replace the second column of the second row with the input field.

You can also use the wrap method to wrap a specific element in the row with the input field:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').wrap('<input type="text" name="newInput" />');

This will wrap the second column of the second row with the input field.

You can also use the unwrap method to unwrap a specific element in the row and append the input field:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').unwrap().append('<input type="text" name="newInput" />');

This will unwrap the second column of the second row and append the input field.

You can also use the wrapInner method to wrap the content of a specific element in the row with the input field:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').wrapInner('<input type="text" name="newInput" />');

This will wrap the content of the second column of the second row with the input field.

You can also use the unwrapInner method to unwrap the content of a specific element in the row and append the input field:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').unwrapInner().append('<input type="text" name="newInput" />');

This will unwrap the content of the second column of the second row and append the input field.

You can also use the wrapAll method to wrap all the elements in a specific element in the row with the input field:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').wrapAll('<input type="text" name="newInput" />');

This will wrap all the elements in the second column of the second row with the input field.

You can also use the unwrapAll method to unwrap all the elements in a specific element in the row and append the input field:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').unwrapAll().append('<input type="text" name="newInput" />');

This will unwrap all the elements in the second column of the second row and append the input field.

You can also use the wrapInnerAll method to wrap the content of all the elements in a specific element in the row with the input field:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').wrapInnerAll('<input type="text" name="newInput" />');

This will wrap the content of all the elements in the second column of the second row with the input field.

You can also use the unwrapInnerAll method to unwrap the content of all the elements in a specific element in the row and append the input field:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').unwrapInnerAll().append('<input type="text" name="newInput" />');

This will unwrap the content of all the elements in the second column of the second row and append the input field.

You can also use the wrapAll method with a function to generate the input field and wrap it around all the elements in the row:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').wrapAll(function() {
  return '<input type="text" name="newInput" />';
});

This will generate a new input field with the name "newInput" and wrap it around all the elements in the second column of the second row.

You can also use the unwrapAll method with a function to generate the input field and unwrap it from all the elements in the row:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').unwrapAll(function() {
  return '<input type="text" name="newInput" />';
});

This will generate a new input field with the name "newInput" and unwrap it from all the elements in the second column of the second row.

You can also use the wrapInnerAll method with a function to generate the input field and wrap it around the content of all the elements in the row:

$('#myTable tr:eq(1)').find('.myRow').find('td:eq(1)').wrapInnerAll(function() {
  return '<input type="text" name="newInput" />';
});

This will generate a new input field with the name "newInput" and wrap it around the content of all the elements in the second column of the second row.

You can also use the unwrapInnerAll method with a function to generate the input field and unwrap it from the content of all the elements in the row:


$('#myTable tr:eq(1

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Add a new input in a row using jquery